ÌâÄ¿ÄÚÈÝ
¢ñ.(1)ÔÚÒ»ÃܱÕÈÝÆ÷ÖÐÒ»¶¨Á¿A¡¢BµÄ»ìºÏÆøÌå·¢Éú·´Ó¦£ºaA(g)£«bB(g)
cC(s)£«dD(g)£¬Æ½ºâʱ²âµÃAµÄŨ¶ÈΪ0.60 mol/L£¬±£³ÖζȲ»±ä£¬½«ÈÝÆ÷µÄÈÝ»ýÀ©´óµ½ÔÀ´µÄ3±¶£¬ÔÙ´ïÆ½ºâʱ£¬²âµÃAµÄŨ¶È½µÎª0.20 mol/L¡£ÏÂÁÐÓйØÅжÏÒ»¶¨ÕýÈ·µÄÊÇ
A£®Æ½ºâÏòÕý·´Ó¦·½ÏòÒÆ¶¯
B£®AµÄת»¯ÂÊÔö´ó
C£®DµÄÌå»ý·ÖÊýÔö´ó
D£®a£«b<c£«d
(2)¢Ù25 ¡æ£¬Á½ÖÖËáµÄµçÀëÆ½ºâ³£ÊýÈçÏÂ±í¡£
Ka1 | Ka2 | |
H2SO3 | 1.3¡Á10£2 | 6.3¡Á10£8 |
H2CO3 | 4.2¡Á10£7 | 5.6¡Á10£11 |
HSO3£µÄµçÀëÆ½ºâ³£Êý±í´ïʽK£½__________________¡£
¢ÚH2SO3ÈÜÒººÍNaHCO3ÈÜÒº·´Ó¦µÄÖ÷ÒªÀë×Ó·½³ÌʽΪ£º______________________¡£
¢Û¸ù¾ÝH2SO3µÄµçÀë³£ÊýÊý¾Ý£¬ÅжÏNaHSO3ÈÜÒºÏÔËáÐÔ»¹ÊÇÏÔ¼îÐÔ£¿
¢ò.0.98 gCu(OH)2ÑùÆ·ÊÜÈÈ·Ö½âµÄÈÈÖØÇúÏß(ÑùÆ·ÖÊÁ¿ËæÎ¶ȱ仯µÄÇúÏß)ÈçͼËùʾ¡£
![]()
Çë»Ø´ðÏÂÁÐÎÊÌ⣺
(1)ÊÔÈ·¶¨1 100 ¡æÊ±ËùµÃ¹ÌÌåBµÄ»¯Ñ§Ê½(ÒªÇóд³öÍÆÀí»ò¼ÆËã¹ý³Ì)¡£
(2)¹ÌÌåAÔÚÒ»¶¨Ìõ¼þÏÂÄÜÓëÒ»ÖÖÄÜʹʪÈóµÄºìɫʯÈïÊÔÖ½±äÀ¶µÄÆøÌå·´Ó¦£¬µÃµ½ºìÉ«¹ÌÌåµ¥ÖÊºÍÆøÌåµ¥ÖÊ£¬Ôò¸Ã·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ£º___________________£»Èô·´Ó¦ÖÐ×ªÒÆ0.015 molµç×Ó£¬ÔòÏûºÄ»¹Ô¼ÁµÄÎïÖʵÄÁ¿Îª________________¡£
(3)È¡ÉÙÁ¿¹ÌÌåBÓÚÊÔ¹ÜÖУ¬¼ÓÈë×ãÁ¿µÄÏ¡ÁòËáµÃµ½À¶É«ÈÜÒº£¬Í¬Ê±¹Û²ìµ½ÊÔ¹ÜÖл¹ÓкìÉ«¹ÌÌå´æÔÚ£¬¸Ã·´Ó¦µÄÀë×Ó·½³ÌʽΪ£º________________________¡£