1. 先圈一圈,再算一算。

55 - 8 = □
先算:□ - □ = □
再算:□ + □ = □

46 - 7 = □
先算:□ - □ = □
再算:□ + □ = □
答案:
55 - 8 = 47
先算:15 - 8 = 7
再算:40 + 7 = 47
46 - 7 = 39
先算:16 - 7 = 9
再算:30 + 9 = 39
解析:

1. 对于 55 - 8:
先圈一圈:从55中圈出5根(个位)减8,不够减,所以从十位借1,变成15减8。
先算:15 - 8 = 7
再算:40 + 7 = 47
2. 对于 46 - 7:
先圈一圈:从46中圈出6根(个位)减7,不够减,所以从十位借1,变成16减7。
先算:16 - 7 = 9
再算:30 + 9 = 39
2. 想一想差的十位上是几。
42 - 6 = □6 86 - 4 = □2 76 - 9 = □7 53 - 9 = □4
25 - 8 = □7 94 - 8 = □6 48 - 5 = □3 25 - 7 = □8
答案:3,8,6,4,1,8,4,1
解析:
42-6:个位2-6不够减,从十位借1,十位4变3,差的十位是3;
86-4:个位6-4够减,十位8不变,差的十位是8;
76-9:个位6-9不够减,从十位借1,十位7变6,差的十位是6;
53-9:个位3-9不够减,从十位借1,十位5变4,差的十位是4;
25-8:个位5-8不够减,从十位借1,十位2变1,差的十位是1;
94-8:个位4-8不够减,从十位借1,十位9变8,差的十位是8;
48-5:个位8-5够减,十位4不变,差的十位是4;
25-7:个位5-7不够减,从十位借1,十位2变1,差的十位是1。
3. 竖式计算。

$\begin{array}{r}83\\-7\\\hline\end{array}$
$\begin{array}{r}46\\-9\\\hline\end{array}$
$\begin{array}{r}91\\-4\\\hline\end{array}$
$\begin{array}{r}47\\-8\\\hline\end{array}$
$\begin{array}{r}32\\-4\\\hline\end{array}$
$\begin{array}{r}45\\-6\\\hline\end{array}$
$\begin{array}{r}51\\-3\\\hline\end{array}$
$\begin{array}{r}62\\-9\\\hline\end{array}$
答案:$\begin{array}{r}83\\-7\\\hline76\end{array}$
$\begin{array}{r}46\\-9\\\hline37\end{array}$
$\begin{array}{r}91\\-4\\\hline87\end{array}$
$\begin{array}{r}47\\-8\\\hline39\end{array}$
$\begin{array}{r}32\\-4\\\hline28\end{array}$
$\begin{array}{r}45\\-6\\\hline39\end{array}$
$\begin{array}{r}51\\-3\\\hline48\end{array}$
$\begin{array}{r}62\\-9\\\hline53\end{array}$
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