ÌâÄ¿ÄÚÈÝ

16£®¸Ë³ÓÊÇÖйú¹Å´úÑØÓÃÖÁ½ñµÄ³£ÓòâÁ¿¹¤¾ß£¬Ä³´Î×ÛºÏʵ¼ù»î¶¯ÖУ¬Ð¡Ã÷ËùÔڻС×éÓÃľ¸Ë¡¢Ìú¿é¡¢³Ó¹³¡¢Ï¸ÏßµÈÖÆ×÷ÁËÒ»°Ñ¡°¸Ë³Ó¡±Èçͼ¼×Ëùʾ£®ËûÃÇÔÚÖÆ×÷¹ý³ÌÖÐѧϰÁË´óÁ¿¹ØÓڸ˳ӵÄ֪ʶ£¬²¢Ìá³öÁËһϵÁÐÎÊÌ⣮
ÎÊÌâÒ»£ºÈçºÎ±ê×¢¸Ë³ÓµÄ¿Ì¶È£¿
ÎÊÌâ¶þ£º¸Ë³ÓµÄ¿Ì¶ÈÊǾùÔȵÄÂð£¿
ÎÊÌâÈý£ºÈçºÎÔö´ó¸Ë³ÓµÄÁ¿³Ì£¿¡­

£¨1£©¹ØÓڿ̶ȣ¬ËûÃDzéÔĵ½ÁËÈçÏÂ×ÊÁÏ£ºÈçͼÒÒËùʾΪ¸Ë³ÓµÄʾÒâͼ£¬µãOΪÌáŦ£¨Ï൱Óڸܸ˵ÄÖ§µã£©£¬CΪ¶¨Ðǵ㣬G0Ϊ³Ó¸Ë¡¢³Ó¹³µÄ×ÔÖØ£¬ÖØÐÄÔÚµãB´¦£¬³ÓíÈÖØÎªG1£®²»¹ÒÖØÎÇÒ³ÓíÈÔÚ¶¨Ðǵãʱ£¬¸Ë³ÓÔÚˮƽλÖÃÆ½ºâ£ºG1•OC=G0•OB£®µ±ÔÚ³Ó¹³ÉϹÒÒ»ÖØÎïGx£¬³ÓíÈÒÆµ½¾à¶¨Ðǵãx´¦Ê±£¬¸Ë³Ó¸ÕºÃÔÚˮƽλÖÃÆ½ºâ£ºG1£¨x+OC£©=Gx•OA+G0OB
¿ÉµÃ£»x=$\frac{{G}_{x}}{{G}_{1}}$•OA£®ÓÉÉÏÊöÍÆµ¼¿ÉµÃ£¬xÓëGx³ÉÕý±È£¬Òò´Ë¸Ë³ÓµÄ¿Ì¶ÈÊǾùÔȵģ¨Ñ¡Ìî¡°¾ùÔȵġ±»ò¡°²»¾ùÔȵġ±£©£»ÔÚÉÏÊö×ÊÁÏÖУ¬¸Ë³Óÿ´Î¶¼Ðèµ÷½Úµ½Ë®Æ½Î»ÖÃÆ½ºâ£¬ÕâÑù²Ù×÷µÄºÃ´¦ÊDZãÓÚ²âÁ¿Á¦±Û£®
£¨2£©²Ù×÷¹ý³ÌÖУ¬Ð¡Ã÷ÔÚÓÒ²à¹Ò¹³ÉϹÒÒ»ÖØÎ²âµÃOAΪ5cm£¬xΪ50cm£¬ÓÖÒÑÖª³ÓíÈÖÊÁ¿Îª50g£»Çëͨ¹ý¼ÆËã°ïÖúСÃ÷±ê×¢´ËλÖÃËù´ú±íµÄÎïÌåÖÊÁ¿£®
£¨3£©Ð¡Ã÷ÔÚµ÷²é¹ý³ÌÖл¹·¢ÏÖ£¬Êг¡Éϵĸ˳ÓÍùÍùÓÐA¡¢BÊÇÁ½¸ö²»Í¬Á¿³ÌµÄÌáŦ£¨Èçͼ±ûËùʾ£©£¬³Ó¹³C´¦Ðü¹Ò±»²âÎÌáÆðÌáŦA»òB£¬ÔÚ³Ó¸ËEÉÏÒÆ¶¯³ÓíÈD£¬´ïµ½Æ½ºâºó£¬¸ù¾Ý³ÓíȵÄλÖÿÉÒÔÔÚ³Ó¸ËÉ϶Á³ö±»²âÎïµÄÖÊÁ¿£®
Óйظø˳ÓÏÂÁÐÅжÏÖÐÕýÈ·µÄÊÇB
A£®ËüÖ»ÄܲâÁ¿±È³ÓíÈÖÊÁ¿´óµÄÎïÌå
B£®ÓÃÌáŦAʱ±ÈÓÃÌáŦBʱµÄÁ¿³Ì¸ü´ó
C£®½«³ÓíÈÖÊÁ¿¼õÉÙ£¬Ôò¸Ã³ÓµÄ¶ÁÊý½«Æ«Ð¡
D£®Ö»Óе±³Ó¸ËµÄ´Öϸ¾ùÔÈʱ£¬¸Ë³ÓµÄ¿Ì¶È²ÅÊǾùÔȵģ®

·ÖÎö £¨1£©¢Ù¸ù¾ÝÖ¸µãµÄ¸ÅÄî·ÖÎö½â´ð£»
¢Ú¿Ì¶ÈÊÇ·ñ¾ùÔÈ£¬È¡¾öÓÚxÓëGxÊÇ·ñ³ÉÕý±È»òÕý±ÈÀýº¯Êý¹ØÏµ£®
¢Û¸Ü¸ËÔÚˮƽλÖÃÆ½ºâʱ£¬Á¦µÄ·½ÏòÓë¸Ü¸Ë´¹Ö±£¬Á¦±ÛµÄ³¤¶È¿ÉÒÔÖ±½Ó´Ó¸Ü¸ËÉ϶Á³öÀ´£®
£¨2£©ÔÚ£¨1£©µÄ»ù´¡ÉÏ£¬¸ù¾Ý¸Ü¸ËƽºâÌõ¼þ·ÖÎö½â´ð¼´¿É£»
£¨3£©¸Ë³ÓÀûÓõÄÊÇ¸Ü¸ËµÄÆ½ºâÌõ¼þ£¬Í¨¹ýÁ¦±ÛµÄ´óС¹ØÏµµÃ³öÎïÌåÖØºÍ³ÓíÈÖØÖ®¼äµÄ¹ØÏµ£¬½ø¶øµÃ³öÎïÌåµÄÖÊÁ¿Óë³ÓíȵÄÖÊÁ¿Ö®¼äµÄ¹ØÏµ£¬²âÁ¿µÄÊÇÎïÌåµÄÖÊÁ¿£»
µ±´Ó³ÓŦA»»µ½³ÓŦBʱ£¬·ÖÎöÁ½±ßÁ¦ºÍÁ¦±ÛµÄ´óСÊÇ·ñ±ä»¯£¬¸ù¾Ý¸Ü¸ËƽºâÌõ¼þµÃ³ö×î´ó²âÁ¿ÖµµÄ±ä»¯£®

½â´ð ½â£º£¨1£©¢ÙÈçͼÒÒËùʾΪ¸Ë³ÓµÄʾÒâͼ£¬ÔÚ³ÆÁ¿ÎïÌåÖÊÁ¿Ê±£¬¸Ü¸ËÎ§ÈÆµãOת¶¯£¬¹ÊµãOÌáŦÏ൱Óڸܸ˵ÄÖ§µã£»
¢ÚÓÉÉÏÊöÍÆµ¼x=$\frac{{G}_{x}}{{G}_{1}}$•OA£¬¿ÉµÃ£¬xÓëGx³ÉÕý±È£¬Òò´Ë¸Ë³ÓµÄ¿Ì¶ÈÊǾùÔȵģ»
¢ÛÁ¦±ÛµÈÓÚÖ§µãµ½Á¦µÄ×÷ÓÃÏߵĴ¹Ö±¾àÀ룬µ±¸Ü¸ËÔÚˮƽλÖÃÆ½ºâʱ£¬Á¦µÄ·½ÏòÓë¸Ü¸Ë´¹Ö±£¬Á¦±Û¿ÉÒԴӸܸ˱ê³ß¿Ì¶ÈÉÏÖ±½Ó¶Á³öÀ´£¬±ãÓÚ²âÁ¿Á¦±Û£®
£¨2£©²»¹ÒÖØÎÇÒ³ÓíÈÔÚ¶¨Ðǵãʱ£¬¸Ë³ÓÔÚˮƽλÖÃÆ½ºâ£ºG1•OC=G0•OB£®
µ±ÔÚ³Ó¹³ÉϹÒÒ»ÖØÎïGx£¬³ÓíÈÒÆµ½¾à¶¨Ðǵãx´¦Ê±£¬¸Ë³Ó¸ÕºÃÔÚˮƽλÖÃÆ½ºâ£ºG1£¨x+OC£©=Gx•OA+G0OB£¬
ÔòÓУºG1x=Gx•OA£¬¼´m1g•x=mxg•OA£¬
ËùÒÔ£¬mx=$\frac{{m}_{1}¡Áx}{OA}$=$\frac{50g¡Á50cm}{5cm}$=500g£»
£¨3£©A¡¢Òò³ÓíȵÄÁ¦±ÛÔÚ´óÓÚËù²âÁ¿ÎïÌåµÄÁ¦±Ûʱ£¬¾Í¿É²âÁ¿±È³ÓíÈÖÊÁ¿´óµÄÎïÌ壮¹ÊA´íÎó£»
B¡¢ÌáŦAʱ±ÈÓÃÌáŦBʱ£¬Ëù²âÁ¿µÄÎïÌåµÄÁ¦±ÛС£¬ÔòÆäÁ¿³Ì´ó£®¹ÊBÕýÈ·£»
C¡¢½«³ÓíÈÖÊÁ¿¼õÉÙ£¬ÔòÒªÔö¼ÓÁ¦±Û£¬Ê¾ÊýÆ«´ó£®¹ÊC´íÎó£»
D¡¢³Ó½Ï׼ʱÒÑÆ½ºâµô³Ó¸ËµÄÖØÁ¦µÄÓ°Ï죬¾«Ï¸¾ù¿É£®¹ÊD´íÎó£®
¹ÊÑ¡B£®
¹Ê´ð°¸Îª£º£¨1£©Ö§µã£»¾ùÔȵģ»±ãÓÚ²âÁ¿Á¦±Û£»
£¨2£©500g£»
£¨3£©B£®

µãÆÀ ±¾Ì⿼²éÁËѧÉú¶Ô¸Ü¸ËƽºâÌõ¼þµÄÕÆÎÕºÍÔËÓã¬Éæ¼°µ½¸Ü¸ËµÄÎåÒªËØ¡¢¸Ü¸ËµÄµ÷½Ú¡¢¸Ë³ÓµÄ²âÁ¿Ô­Àí£¬ÊôÓÚÄÑÌ⣮

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø