ÌâÄ¿ÄÚÈÝ

ÔÚ¡°Ì½¾¿Ëٶȵı仯¡±ÊµÑéÖУ¬ÇëÍê³ÉÒÔÏÂÎÊÌ⣺
£¨1£©¸ÃʵÑéÔ­ÀíÊÇ£º______
£¨2£©ÊµÑéÖÐÐèÒª²âÁ¿£º______¡¢______ËüÃǵIJâÁ¿¹¤¾ß·Ö±ðÊÇ£º______¡¢______
£¨3£©ÓÐͬѧÉè¼ÆÁËÈçϱí¸ñÇëÄãÍê³ÉËüµÄÌîд£º
·³Ìs/cmÔ˶¯Ê±¼ät/sƽ¾ùËÙ¶Èv/£¨cm/s£©
S×Ü=80.00t ×Ü=2.8V=28.6
S1=40.00t1=2.0V1=20.0
S2=S×Ü-S1=40.00t2=0.8V2=
£¨4£©Í¨¹ý±È½ÏV1¡¢V2ÎÒÃǵóö½áÂÛ£ºÐ¡³µÑØÐ±ÃæÏ»¬Ê±ËÙ¶È______£®

½â£º£¨1£©Ì½¾¿Ëٶȵı仯µÄʵÑéÔ­ÀíÊÇÆ½¾ùËٶȹ«Ê½£ºv=£®
£¨2£©ÊµÑéÖÐÐèÒªÓÿ̶ȳ߲âС³µµÄ·³Ì£¬ÓÃÃë±í²âС³µµÄÔ˶¯Ê±¼ä£®
£¨3£©ÓɱíÖÐÊý¾Ý¿ÉÖª£¬Ð¡³µµÄƽ¾ùËÙ¶Èv2===50.0cm/s£®
£¨4£©Óɱí¿ÉÖª£¬v1=20.0cm/s£¬v2=50.0cm/s£¬Óɴ˿ɼû£¬
С³µÑØÐ±ÃæÏ»¬Ê±£¬ËÙ¶ÈÔ½À´Ô½´ó£®
¹Ê´ð°¸Îª£º£¨1£©v=£»£¨2£©Â·³Ì£»Ê±¼ä£»¿Ì¶È³ß£»Í£±í£»
£¨3£©50.0£»£¨4£©Ô½À´Ô½´ó£®
·ÖÎö£º£¨1£©²âËٶȵÄÔ­ÀíÊÇËٶȹ«Ê½£®
£¨2£©ÒªÓÉËٶȹ«Ê½Çó³öËÙ¶È£¬ÐèÒªÓÿ̶ȳ߲âÁ¿ÎïÌåµÄ·³Ì£¬ÓÃÃë±í²â³öÎïÌåµÄÔ˶¯Ê±¼ä£®
£¨3£©ÒÑ֪·³ÌÓëÔ˶¯Ê±¼ä£¬ÓÉÆ½¾ùËٶȹ«Ê½¿ÉÒÔÇó³öС³µµÄƽ¾ùËÙ¶È£®
£¨4£©·ÖÎö±íÖÐʵÑéÊý¾Ý£¬¸ù¾Ýv1¡¢v2µÄ´óСµÃ³ö½áÂÛ£®
µãÆÀ£º±¾Ì⿼²éÁË²âÆ½¾ùËٶȵÄÔ­Àí¡¢ÐèÒª²âÁ¿µÄÁ¿¡¢²âÁ¿¹¤¾ß¡¢Ç󯽾ù¶àÉÙ¡¢ÊµÑéÊý¾Ý·ÖÎöµÈ£¬ËäÈ»Éæ¼°µÄ֪ʶµã½Ï¶à£¬µ«ÄѶȲ»´ó£¬ÊìÁ·ÕÆÎÕ»ù´¡ÖªÊ¶¼´¿ÉÕýÈ·½âÌ⣮
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø