ÌâÄ¿ÄÚÈÝ

7£®ÈçͼËùʾ£¬ÔÚ²âÁ¿Ð¡³µÔ˶¯µÄƽ¾ùËÙ¶ÈʵÑéÖУ¬ÈÃС³µ´ÓÐ±ÃæµÄAµãÓɾ²Ö¹¿ªÊ¼Ï»¬²¢¿ªÊ¼¼ÆÊ±£¬·Ö±ð²â³öС³µµ½´ïBµãºÍCµãµÄʱ¼ä£¬¼´¿ÉËã³öС³µÔÚ¸÷¶ÎµÄƽ¾ùËÙ£®

£¨1£©ÒÑ֪ͼÖÐAB¶ÎµÄ¾àÀësABµÈÓÚ40.0cm£¬²âµÃʱ¼ätAB=1.6s£¬ÔòAB¶ÎµÄƽ¾ùËÙ¶ÈvAB=25.0cm/s
£¨2£©Èç¹ûС³µ¹ýÁËBµã²ÅÍ£Ö¹¼ÆÊ±£¬Ôò²âµÃµÄƽ¾ùËÙ¶ÈvAB»áƫС£®
£¨3£©ÊµÑéÖÐÓ¦¶à´Î²âÁ¿£¬Ã¿´Î²âÁ¿Ê±±ØÐëÈÃС³µ´ÓͬһλÖÃÓɾ²Ö¹¿ªÊ¼Ï»¬£®
£¨4£©vBC£¾vAC £¨Ìî¡°£¾¡±¡¢¡°£¼¡±»ò¡°=¡±£©£®

·ÖÎö £¨1£©ÔËÓù«Ê½v=$\frac{s}{t}$Çó³öAB¶ÎµÄƽ¾ùËÙ¶È£»
£¨2£©ÈÃС³µ¹ýÁËBµã²ÅÍ£Ö¹¼ÆÊ±£¬»áµ¼ÖÂʱ¼äµÄ²âÁ¿½á¹ûÆ«´ó£¬Æ½¾ùËÙ¶È»áÆ«Ð¡£®
£¨3£©Ã¿´Î²âÁ¿Ê±±ØÐëÈÃС³µ´ÓͬһλÖÃÓɾ²Ö¹¿ªÊ¼Ï»¬£¬±£Ö¤Ð¡³µÃ¿´Îͨ¹ýµÄ¾àÀëÏàµÈ£®
£¨4£©Ð¡³µ×ö¼ÓËÙÔ˶¯£¬¿ÉµÃÉϰë¶Î¡¢Ï°ë¶Î·³ÌµÄËÙ¶È´óС¹ØÏµ£®

½â´ð ½â£º
£¨1£©Ð¡³µÔ˶¯¾àÀësAB=40.0cm£¬tAB=1.6s£¬
С³µÍ¨¹ýAB¶ÎµÄƽ¾ùËÙ¶È£ºv=$\frac{s}{t}$=$\frac{40.0cm}{1.6s}$=25.0cm/s£»
£¨2£©Èç¹ûÈÃС³µ¹ýÁËBµã²ÅÍ£Ö¹¼ÆÊ±£¬»áµ¼ÖÂʱ¼äµÄ²âÁ¿½á¹ûÆ«´ó£¬Óɹ«Ê½v=$\frac{s}{t}$Öª£¬Æ½¾ùËÙ¶È»áÆ«Ð¡£®
£¨3£©ÊµÑéÖÐÓ¦¶à´Î²âÁ¿£¬Ó¦±£Ö¤Ð¡³µÃ¿´Îͨ¹ýµÄ¾àÀëÏàµÈ£¬¹Êÿ´Î²âÁ¿Ê±±ØÐëÈÃС³µ´ÓͬһλÖÃAÓɾ²Ö¹¿ªÊ¼Ï»¬£®
£¨4£©Ð¡³µ´ÓAµ½CµÄ¹ý³ÌÖÐ×ö¼ÓËÙÔ˶¯£¬ËÙ¶ÈÔ½À´Ô½´ó£¬¹ÊÔÚBC¶ÎµÄËÙ¶È´óÓÚAC¶ÎµÄËÙ¶È£¬¼´vBC£¾vAC£®
¹Ê´ð°¸Îª£º
£¨1£©25.0£»£¨2£©Ð¡£»£¨3£©Í¬Ò»Î»Ö㻣¨4£©£¾£®

µãÆÀ ±¾Ì⿼²é¡°²âС³µµÄƽ¾ùËÙ¶È¡±µÄʵÑ飬һ¶¨Ñ§»á¶Á³ö·³ÌºÍʱ¼ä£¬°´Æ½¾ùËٶȵ͍Òå´úÈëv=$\frac{s}{t}$Çó³öƽ¾ùËÙ¶È£®

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø