ÌâÄ¿ÄÚÈÝ

 ÔÚˮƽ×ÀÃæÖÐÑëÓÐÒ»¸öÖØÎª7Å£¡¢µ×Ãæ»ýΪ2¡Á10-2Ã×2µÄ±¡±ÚÈÝÆ÷£¬¸ÃÈÝÆ÷ÄÚÊ¢ÓÐÖØÎª49Å£µÄË®£¬ÇÒË®¶ÔÈÝÆ÷µ×²¿µÄѹÁ¦Îª53Å£¡£

¢Ù Çó£ºÈÝÆ÷¶Ô×ÀÃæµÄѹÁ¦FºÍѹǿp¡£

¢Ú Çó£ºÈÝÆ÷ÄÚË®µÄÖÊÁ¿mË®ÓëÌå»ýVË®¡£

¢Û ÔÚ·ÖÎö±¾Ìâ¡°Ë®¶ÔÈÝÆ÷µ×²¿µÄѹǿpË®¡±µÄ¹ý³ÌÖУ¬Ð¡Ã÷ºÍС»ªÁ½Î»Í¬Ñ§Óи÷×Ô²»Í¬Ïë·¨£¬ÈçϱíËù¼Ç¡£

 

 

 

 

 

£¨a£©ÇëÅжϣºÐ¡Ã÷µÄ·ÖÎö¹ý³ÌÊÇ____£»Ð¡»ªµÄ·ÖÎö¹ý³ÌÊÇ____¡££¨¾ùÑ¡Ìî¡°ÕýÈ·¡±»ò¡°´íÎó¡±£©

£¨b£©ÈôÄÜÇóË®¶ÔÈÝÆ÷µ×²¿µÄѹǿpË®£¬Çë¼ÆËã²¢µÃ³ö½á¹û£»Èô²»ÄÜÇóË®¶ÔÈÝÆ÷µ×²¿µÄѹǿpË®£¬Çë¼òҪ˵Ã÷ÀíÓÉ¡£

 

¢Ù F =GË®+ GÈÝ                                                     1·Ö

=7Å£+49Å£=56Å£                                              1·Ö

p=F /S                                                          1·Ö

=56Å£/2¡Á10-2Ã×2=2.8¡Á103ÅÁ                                   1·Ö

¢Ú mË®=GË®/g                                                       1·Ö

=49Å£/9.8Å£/ǧ¿Ë=5ǧ¿Ë                                       1·Ö

VË®=mË®/¦ÑË®                                                      1·Ö

=5ǧ¿Ë/1.0¡Á103ǧ¿Ë/Ã×3= 5¡Á10-3Ã×3                             1·Ö

¢Û£¨a£©´íÎó£»´íÎó                                                 2·Ö

£¨b£©pË®=FË®/ S =53Å£/2¡Á10-2Ã×2=2.65¡Á103ÅÁ

½âÎö:ÂÔ

 

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø