ÌâÄ¿ÄÚÈÝ
¸ø³öÏÂÁÐÆ÷²Ä£ºµçÁ÷±í£¨0¡«0.6A£¬0¡«3A£©Ò»Ö»£¬µçѹ±í£¨0¡«3V£¬0¡«15V£©Ò»Ö»£¬»¬¶¯±ä×èÆ÷£¨0¡«10
£©Ò»Ö»£¬µçÔ´£¨4V£©Ò»¸ö£¬´ý²âµç×èµÄСµÆÅÝ£¨¶î¶¨µçѹ2.5V£¬µç×èÔ¼10
£©Ò»¸ö£¬¿ª¹ØÒ»Ö»£¬µ¼ÏßÈô¸É£¬ÒªÇóÓ÷ü°²·¨²â¶¨Õý³£·¢¹âʱСµÆÅݵÆË¿µÄµç×裬²âÁ¿Ê±£¬Á½±íµÄÖ¸ÕëÒªÇ󯫹ý±íÃæ¿Ì¶ÈµÄÖÐÏß¡£
£¨1£©»³öµç·ͼ£»
£¨2£©µçÁ÷±íµÄÁ¿³ÌÑ¡ £¬µçѹ±íµÄÁ¿³ÌÑ¡ £»
£¨3£©ÏÂÁбØÒªµÄʵÑé²½ÖèÖУ¬ºÏÀí˳ÐòÊÇ ¡£
A. ±ÕºÏ¿ª¹Ø B. ½«²â³öµÄÊý¾ÝÌîÈë±í¸ñÖÐ
C. ¼ÆËã±»²âСµÆÅݵĵÆË¿µç×è D. ¶Á³öµçѹ±í£¬µçÁ÷±íµÄÊýÖµ
E. ¶Ï¿ª¿ª¹Ø F. ½«»¬¶¯±ä×èÆ÷µÄ×èÖµµ÷µ½×î´ó
G. ¶ÔÕÕµç·ͼÁ¬ºÃµç· H. µ÷½Ú»¬¶¯±ä×èÆ÷£¬Ê¹µçѹ±íµÄʾÊýΪ2.5V
£¨1£©ÈçͼËùʾ
![]()
£¨2£©0¡«0.6A 0¡«3V
£¨3£©GFAHDBEC
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿