ÌâÄ¿ÄÚÈÝ

¡¾ÌâÄ¿¡¿Ð¡ÀöͬѧÀûÓÃÌìÆ½ºÍÁ¿Í²²âÁ¿×Ô¼ºÅäÖÆµÄÑÎË®µÄÃܶȡ£

(1)ʵÑé²½ÖèÈçÏ£º

¢Ù°ÑÌìÆ½·ÅÔÚˮƽ̨ÉÏ£¬·¢ÏÖÖ¸ÕëλÖÃÈçͼ¼×Ëùʾ£¬´ËʱӦ½«Æ½ºâÂÝĸÏò_________ÒÆ¶¯£¬Ê¹ÌìÆ½Æ½ºâ£»

¢ÚÔÚ²£Á§±­ÖÐÊ¢ÈëÑÎË®£¬·ÅÔÚµ÷½ÚºÃµÄÌìÆ½×óÅ̳ÆÁ¿£¬µ±ÌìÆ½ÖØÐÂÆ½ºâʱ£¬¼ÇÏÂíÀÂëºÍÓÎÂëµÄ¶ÁÊýΪ126.2g£»

¢Û°Ñ²£Á§±­ÖеIJ¿·ÖÑÎË®µ¹ÈëÁ¿Í²ÖУ¬ÈçͼÒÒËùʾ£¬¼ÇÏÂÁ¿Í²ÖÐÑÎË®µÄÌå»ýΪ_________cm3£»

¢Ü°Ñ²£Á§±­ºÍÊ£ÓàÑÎË®·ÅÔÚÌìÆ½×óÅÌÖгÆÁ¿£¬µ±ÌìÆ½ÖØÐÂÆ½ºâʱ£¬ËùÓÃíÀÂë¡¢ÓÎÂëµÄλÖÃÈçͼ±ûËùʾΪ_________g£»

¢Ý¼ÆËã³öÑÎË®µÄÖÊÁ¿ÊÇ_______g£¬ÃܶÈÊÇ________g/cm3£½______________kg/m3£»

(2)Èç¹ûСÀöÔÚʵÑé¹ý³ÌÖÐÏȲâÁ¿ÑÎË®µÄÌå»ý£¬ÔÙ²âÁ¿ÑÎË®µÄÖÊÁ¿£¬Ôò²âµÃµÄÃܶÈÖµ»áÆ«_________¡£

¡¾´ð°¸¡¿ÓÒ 60 54.2 72 1.2 1.2¡Á103 С

¡¾½âÎö¡¿

(1)[1]´Óͼ¼×¿ÉÒÔ¿´µ½£¬Ö¸ÕëÍù×óÆ«£¬Õâ˵Ã÷×ó±ß±È½ÏÖØ£¬ÄÇô´ËʱӦ½«Æ½ºâÂÝĸÏòÓÒÒÆ¶¯£¬Ê¹ÌìÆ½Æ½ºâ£»

[2]´ÓͼÒÒ¿ÉÒÔ¿´µ½£¬Á¿Í²ÖÐÑÎË®µÄÌå»ýΪ

[3][4][5][6]´Óͼ±û¿ÉÒÔ¿´µ½£¬²£Á§±­ºÍÊ£ÓàÑÎË®ÊÇ

ÄÇô¿ÉÒÔÖªµÀ£¬Á¿Í²ÖÐÑÎË®µÄÖÊÁ¿ÊÇ

ÑÎË®µÄÃܶÈÊÇ

(2)[7]Èç¹ûСÀöÔÚʵÑé¹ý³ÌÖÐÏȲâÁ¿ÑÎË®µÄÌå»ý£¬ÔÙ²âÁ¿ÑÎË®µÄÖÊÁ¿£¬ÕâʱËý»á°ÑÑÎË®µ¹Èë²£Á§±­ÖУ¬Á¿Í²»áÓÐÒ»µãÑÎË®¸½ÔÚÉÏÃæ£¬ÄÇôËù²âÁ¿ÑÎË®µÄÖÊÁ¿Æ«Ð¡£¬¸ù¾Ý¿ÉÖª£¬²âµÃµÄÃܶÈÖµ»áƫС¡£

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø