ÌâÄ¿ÄÚÈÝ

¡¾ÌâÄ¿¡¿¡°¶Åɯ·òÈËÀ¯Ïñ¹Ý¡±ÊÇÊÀ½çÉÏÖøÃûµÄÀ¯Ïñ¹ÝÖ®Ò»£¬¹ÝÄÚÓÐÐí¶àÃûÈËÀ¯Ïñ¡£ÈçͼËùʾΪҦÃ÷µÄÀ¯Ïñ¡£

(1)ÒÑÖªÒ¦Ã÷µÄÌåÖØÎª140kg£¬ÈËÌåµÄÃܶȺÍË®µÄÃܶȣ¨1¡Á103kg/m3£©²î²»¶à£¬ÔòÒ¦Ã÷µÄÌå»ý´óÔ¼ÊǶàÉÙ£¿

(2)¼ÙÉèÓÃÀ¯£¨ÃܶÈΪ0.9¡Á103kg/m3£©À´×öÒ»¸öͬÑùÌå»ýµÄ¡°Ò¦Ã÷¡±£¬²âµÃÆäÖÊÁ¿Îª117kg¡£Õâ¸ö¡°À¯ÏñÒ¦Ã÷¡±ÊÇ¿ÕÐÄ»¹ÊÇʵÐÄ£¿Èç¹ûÊÇ¿ÕÐÄ£¬¿ÕÐIJ¿·ÖµÄÌå»ýÊǶàÉÙ£¿

¡¾´ð°¸¡¿(1) 0.14m3£»(2)¿ÕÐÄ£¬0.01m3

¡¾½âÎö¡¿

(1)Ò¦Ã÷µÄÌå»ý

V==0.14m3

(2)À¯ÏñÒ¦Ã÷µÄÌå»ý

VÀ¯= =0.13m3

ÓÉVÀ¯£¼V¿ÉÖª£¬Õâ¸ö¡°À¯ÏñÒ¦Ã÷¡±ÊÇ¿ÕÐĵģ¬Ôò¿ÕÐIJ¿·ÖµÄÌå»ý

V¿Õ=V-VÀ¯=0.14m3-0.13m3=0.01m3

´ð£º(1)Ò¦Ã÷µÄÌå»ý´óÔ¼ÊÇ0.14m3£»

(2)Õâ¸ö¡°À¯ÏñÒ¦Ã÷¡±ÊÇ¿ÕÐĵģ¬¿ÕÐIJ¿·ÖµÄÌå»ýÊÇ0.01m3¡£

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

¡¾ÌâÄ¿¡¿ÔĶÁÏÂÃæ¶ÌÎÄ£¬»Ø´ðÎÊÌâ¡£

Ì«ÑôÄÜÈÈË®Æ÷

Ì«ÑôÄÜÈÈË®Æ÷ÄÜÀûÓÃÌ«ÑôÄܰÑË®´ÓµÍμÓÈȵ½¸ßΣ¬ÒÔÂú×ãÈËÃÇÈÕ³£Éú»îµÄÐèÒª£®Ëü¾ßÓа²È«¡¢½ÚÄÜ¡¢»·±£µÈÓŵ㣮Èçͼ£¬µ±Ì«Ñô¹âÈëÉäµ½ºÚÉ«µÄÎüÈȲãÉÏʱ£¬ºÚÉ«ÎüÈȲãÄܰÑÌ«ÑôÄܸüÓÐЧµØ×ª»¯ÎªÄÚÄÜ£¬½«¹ÜÄÚµÄË®¼ÓÈÈ£®Ð¡Ã÷¼ÒÀïÌ«ÑôÄÜÈÈË®Æ÷ÅäÓÐһ̨µç¶¯Ë®±Ã£¬Ëüµç»úµÄÃúÅÆÈçÏ£º

ÓÐÒ»Ì죬СÃ÷ΪÁË̽¾¿¼ÒÀïÌ«ÑôÄÜÈÈË®Æ÷µÄ½ÚÄÜЧ¹û£¬Ã¿¸ô1 Сʱ¼Ç¼װÂúˮʱ̫ÑôÄÜÈÈË®Æ÷µÄˮΣ¬¼Ç¼Êý¾ÝÈçϱí

Çë»Ø´ðÒÔÏÂÎÊÌ⣺

£¨1£©²£Á§ÎüÈȹÜÄÚÏò¹âÒ»²àµÄË®ÎüÊÕÌ«ÑôÄÜÊÇͨ¹ý_____________·½Ê½½øÐУ¬Ëæ×ÅË®ÎÂÉý¸ß£¬Æä_________ÄÜÔö¼Ó£®

£¨2£©ÄÄһСʱ̫ÑôÄÜÈÈË®Æ÷ÉýÎÂËÙ¶È×î¿ì£¿´ð£º__________ ÖÁ ___________

£¨3£©Ë®±Ã¹¤×÷ʱ£¬½«Ë®´ÓµØÃæÔÈËÙÌáÉýÖÁÎÝÃæÉÏÌ«ÑôÄÜÈÈË®Æ÷ÄÚ£¬Ë®µÄ¶¯ÄÜ_________£¬ÖØÁ¦ÊÆÄÜ__________£¨Ôö´ó¡¢¼õС¡¢²»±ä£©¡£

£¨4£©ÈôʹÓÃÅäÌ×µç»úÒÔ0.2kWÕý³£¹¤×÷ʱ£¬ÔÚ5minÄÚ½«×ö¹¦_________J.

£¨5£©Ê¹ÓôËÅäÌ×¶¯Á¦»úµÄË®±ÃÔÚ5minÄÚÄܽ«ÖØ_________NµÄË®³éµ½16m¸ßµÄË®ÏäÀï.

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø