附加题:用换元法解方程(x+
)2-(x+
)=1,若设y=x+
,则原方程可化为( )
| 2 |
| x |
| 2 |
| x |
| 2 |
| x |
| A、y2-y+1=0 |
| B、y2+y+1=0 |
| C、y2+y-1=0 |
| D、y2-y-1=0 |
方程x2=x+1的根是( )
A、x=
| ||||
B、x=
| ||||
C、x=±
| ||||
D、x=
|
| 2 |
| x |
| 2 |
| x |
| 2 |
| x |
| A、y2-y+1=0 |
| B、y2+y+1=0 |
| C、y2+y-1=0 |
| D、y2-y-1=0 |
A、x=
| ||||
B、x=
| ||||
C、x=±
| ||||
D、x=
|