4.
如图,在直线y=$\frac{\sqrt{3}}{3}$x+1上取一点A1,以O、A1为顶点做第一个等边三角形OA1B1,再在直线上取一点A2,以A2、B1为顶点作第二个等边三角形A2B1B2,…,一直这样做下去,则第10个等边三角形的边长为( )
0 309325 309333 309339 309343 309349 309351 309355 309361 309363 309369 309375 309379 309381 309385 309391 309393 309399 309403 309405 309409 309411 309415 309417 309419 309420 309421 309423 309424 309425 309427 309429 309433 309435 309439 309441 309445 309451 309453 309459 309463 309465 309469 309475 309481 309483 309489 309493 309495 309501 309505 309511 309519 366461
| A. | ($\frac{\sqrt{3}}{3}$)9 | B. | ($\frac{\sqrt{3}}{3}$)10 | C. | 29•$\sqrt{3}$ | D. | 210•$\sqrt{3}$ |