一钢铁厂用两种铁矿石炼铁,甲种矿石含铁68%,乙种含铁63%,要配成含铁65%的矿石100吨,两种矿石应各取多少吨?若设取甲种矿石为x吨,列出方程为( )
| A、68%x+(100-x)×63%=100×65% |
| B、(68%+63%)x=100×65% |
| C、68x+(100-x)×63=100×65% |
| D、63%x+(100-x)×68%=100×65% |
| A、68%x+(100-x)×63%=100×65% |
| B、(68%+63%)x=100×65% |
| C、68x+(100-x)×63=100×65% |
| D、63%x+(100-x)×68%=100×65% |