如图,E、F分别是正方形ABCD的边BC、CD上的点,BE=CF,连接AE、BF.将△ABE绕正方形的对角线交点O按顺时针方向旋转到△BCF,则旋转角是( )

A.45°
B.120°
C.60°
D.90°
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A.45°
B.120°
C.60°
D.90°