题目内容
先化简,再求值:(| 2x-1 |
| x+1 |
| x |
| x-1 |
| x2-1 |
| x |
| 2 |
分析:先将分式化简,再把x的值代入,化简二次根式即可.
解答:解:原式=
•
,
=
,
=x-4+
,
∵x=
-1,
∴原式=
-1-4+
,
=2
-4.
| (2x-1)(x-1)-x(x+1) |
| x2-1 |
| x2-1 |
| x |
=
| x2-4x+1 |
| x |
=x-4+
| 1 |
| x |
∵x=
| 2 |
∴原式=
| 2 |
| 1 | ||
|
=2
| 2 |
点评:本题考查了二次根式的化简与求值,是基础知识比较简单.
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