题目内容
解方程(1)
-
=1-
(2)
[x-
(x-1)]=
(x-1).
| x+2 |
| 5 |
| x-1 |
| 2 |
| x |
| 5 |
(2)
| 1 |
| 2 |
| 1 |
| 2 |
| 2 |
| 3 |
(1)
-
=1-
,
去分母得:2(x+2)-5(x-1)=10-2x,
去括号得:2x+4-5x+5=10-2x,
移项得:2x-5x+2x=10-4-5,
合并同类项得:-x=1,
∴x=-1.
(2)
[x-
(x-1)]=
(x-1),
去括号得:
x-
x+
=
x-
,
去分母得:6x-3x+3=8x-8,
移项、合并同类项得:-5x=-11,
解得:x=
.
| x+2 |
| 5 |
| x-1 |
| 2 |
| x |
| 5 |
去分母得:2(x+2)-5(x-1)=10-2x,
去括号得:2x+4-5x+5=10-2x,
移项得:2x-5x+2x=10-4-5,
合并同类项得:-x=1,
∴x=-1.
(2)
| 1 |
| 2 |
| 1 |
| 2 |
| 2 |
| 3 |
去括号得:
| 1 |
| 2 |
| 1 |
| 4 |
| 1 |
| 4 |
| 2 |
| 3 |
| 2 |
| 3 |
去分母得:6x-3x+3=8x-8,
移项、合并同类项得:-5x=-11,
解得:x=
| 11 |
| 5 |
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