题目内容
计算:
(1)3
-2
-4
+3
(2)(
-1)2-(
)-1+
+(1-
)0
(3)
×2
÷
(4)
+a
-b
-
.
(1)3
| 2 |
| 12 |
|
| 48 |
(2)(
| 3 |
| 1 |
| 2 |
| 4 | ||
|
| 2 |
(3)
| a |
| b |
| a2b |
|
| 2 |
| 3 |
| a3b |
(4)
| a2b |
|
|
| ab2 |
(1)原式=3
-4
-
+12
=2
+8
;
(2)原式=3-2
+1-2+2(
-1)+1=3-2
+1-2+2
-2+1=1;
(3)原式=
•2•
=
=
•
=3;
(4)原式=a
+
-
-b
=a
-b
.
| 2 |
| 3 |
| 2 |
| 3 |
| 2 |
| 3 |
(2)原式=3-2
| 3 |
| 3 |
| 3 |
| 3 |
(3)原式=
| a |
| b |
| 3 |
| 2 |
a2b•
|
| 3a |
| b |
|
| 3a |
| b |
| b |
| a |
(4)原式=a
| b |
| ab |
| ab |
| a |
| b |
| a |
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