题目内容

分解因式:
(1)x2y-4y;                
(2)ax2-4ax+4a
(3)(x-y)2+4(x-y)
(4)(a2+b22-4a2b2
(1)原式=y(x2-4)
=y(x+2)(x-2);

(2)原式=a(x2-4x+4)
=a(x-2)2
(3)原式=(x-y)(x-y+4);

(4)原式=(a2+b2+2ab)(a2+b2-2ab)
=(a+b)2(a-b)2
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