题目内容
先化简,再求值:(1+| 1 |
| x |
| x2-1 |
| x |
| 2 |
分析:本题要先将分式化简,再把x的值代入求解.
解答:解:原式=
÷
=
÷
=
•
=
,
当x=
时,原式=
=
+1.
| x+1 |
| x |
| x2-1 |
| x |
=
| x+1 |
| x |
| (x+1)(x-1) |
| x |
=
| x+1 |
| x |
| x |
| (x+1)(x-1) |
=
| 1 |
| x-1 |
当x=
| 2 |
| 1 | ||
|
| 2 |
点评:分式的混合运算,要特别注意运算顺序以及符号的处理.
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