题目内容
比较大小:-
.
| 22 |
| 7 |
<
<
-π,-1| 1 |
| 2 |
>
>
-1| 2 |
| 3 |
分析:先计算出|-
|=
≈3.142857,|-π|=π≈3.1415;|-1
|=1
=
,|-1
|=1
=
,然后根据负数的绝对值越大,这个数越小进行大小比较.
| 22 |
| 7 |
| 22 |
| 7 |
| 1 |
| 2 |
| 1 |
| 2 |
| 9 |
| 6 |
| 2 |
| 3 |
| 2 |
| 3 |
| 10 |
| 6 |
解答:解:∵|-
|=
≈3.142857,|-π|=π≈3.1415,
∴-
<-π;
∵|-1
|=1
=
,|-1
|=1
=
,
∴-1
>-1
.
故答案为<>.
| 22 |
| 7 |
| 22 |
| 7 |
∴-
| 22 |
| 7 |
∵|-1
| 1 |
| 2 |
| 1 |
| 2 |
| 9 |
| 6 |
| 2 |
| 3 |
| 2 |
| 3 |
| 10 |
| 6 |
∴-1
| 1 |
| 2 |
| 2 |
| 3 |
故答案为<>.
点评:本题考查了有理数大小比较:正数大于0,负数小于0;负数的绝对值越大,这个数越小.
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