题目内容
(1)计算(结果保留根号):
①|1-
|=
②|
-
|=
③|
-
|=
④|
-
|=
(2)计算(结果保留根号):
|
-
|+|
-
|+|
-
|+…|
-
|
①|1-
| 2 |
②|
| 2 |
| 3 |
③|
| 3 |
| 4 |
④|
| 4 |
| 5 |
(2)计算(结果保留根号):
|
| 2 |
| 3 |
| 3 |
| 4 |
| 4 |
| 5 |
| 2013 |
| 2014 |
考点:实数的运算
专题:
分析:(1)直接进行绝对值的化简即可求解;
(2)先进行绝对值的化简,然后合并.
(2)先进行绝对值的化简,然后合并.
解答:解:(1)①原式=
-1;
②原式=
-
;
③原式=
-
=2-
;
④原式=
-
=
-2;
故答案为:
-1,
-
,2-
;
-2;
(2)原式=
-
+
-
+
-
+…
-
=
-
.
| 2 |
②原式=
| 3 |
| 2 |
③原式=
| 4 |
| 3 |
| 3 |
④原式=
| 5 |
| 4 |
| 5 |
故答案为:
| 2 |
| 3 |
| 2 |
| 3 |
| 5 |
(2)原式=
| 3 |
| 2 |
| 4 |
| 3 |
| 5 |
| 4 |
| 2014 |
| 2013 |
| 2014 |
| 2 |
点评:本题考查了实数的运算,解答本题的关键是掌握绝对值的化简法则.
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