题目内容
先化简,再求值:(1+
)÷
,其中x=
.
| 1 |
| x-1 |
| x |
| x2-1 |
| 1 | ||
|
原式=
×
=x+1
∵x=
=
-1,
∴当x=
-1时,
原式=
-1+1=
.
| x |
| x-1 |
| (x+1)(x-1) |
| x |
∵x=
| 1 | ||
|
| 2 |
∴当x=
| 2 |
原式=
| 2 |
| 2 |
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题目内容
| 1 |
| x-1 |
| x |
| x2-1 |
| 1 | ||
|
| x |
| x-1 |
| (x+1)(x-1) |
| x |
| 1 | ||
|
| 2 |
| 2 |
| 2 |
| 2 |