题目内容


已知:如图,在平面直角坐标系xOy中,直线轴交于点A (– 2,0),与反比例函数在第一象限内的图象交于点B (2,n),连结BO,若

(1)求该反比例函数的解析式和直线的解析式;
(2)若直线AB轴的交点为C,求△OCB的面积.

(1) ;
(2)解析:
解:(1) 由,得
∵点在第一象限内,
.∴.····················································· (2分)
∴点的坐标是.······················································· (3分)
设该反比例函数的解析式为
将点的坐标代入,得,∴.································ (4分)
∴反比例函数的解析式为:.·········································· (5分)
设直线的解析式为
将点的坐标分别代入,得···························· (6分)
解得 ···································································· (7分)
∴直线的解析式为.············································ (8分)
(2) 在中,令,得
∴点的坐标是.∴.······································· (9分)
.········································ (10分)
练习册系列答案
相关题目

违法和不良信息举报电话:027-86699610 举报邮箱:58377363@163.com

精英家教网