题目内容
计算:(1)(-10)÷(-
)×5
(2)[1-(1-0.5×
)]×[2-(-3)2].
| 1 |
| 5 |
(2)[1-(1-0.5×
| 1 |
| 3 |
(1)(-10)÷(-
)×5
=(-10)×(-5)×5
=250;
(2)[1-(1-0.5×
)]×[2-(-3)2]
=[1-(1-
)]×(2-9)
=(1-1+
)×(-7)
=
×(-7)
=-
.
| 1 |
| 5 |
=(-10)×(-5)×5
=250;
(2)[1-(1-0.5×
| 1 |
| 3 |
=[1-(1-
| 1 |
| 6 |
=(1-1+
| 1 |
| 6 |
=
| 1 |
| 6 |
=-
| 7 |
| 6 |
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