题目内容
计算：(
+
)÷
=
| 1 |
| x-1 |
| 1 |
| x+1 |
| 3x |
| 1-x2 |
-
| 2 |
| 3 |
-
．| 2 |
| 3 |
分析：首先对括号内的式子及进行通分相加，然后把除法转化为乘法运算，进行约分．
解答：解：原式=[
+
]•
=
•
=-
．
故答案是：-
．
| x+1 |
| (x-1)(x+1) |
| x-1 |
| (x-1)(x+1) |
| (1-x)(1+x) |
| 3x |
=
| 2x |
| (x-1)(x+1) |
| (1-x)(1+x) |
| 3x |
=-
| 2 |
| 3 |
故答案是：-
| 2 |
| 3 |
点评：本题主要考查分式的混合运算，通分、因式分解和约分是解答的关键．
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