题目内容
计算:| 1 |
| x-3 |
| 3 |
| x(x-3) |
分析:首先把异分母分式转化成同分母,然后进行加减运算.
解答:解:原式=
-
=
=
.
| x |
| x(x-3) |
| 3 |
| x(x-3) |
=
| x-3 |
| x(x-3) |
=
| 1 |
| x |
点评:归纳提炼:分式的加减运算中,如果是同分母分式,那么分母不变,把分子直接相加减即可;如果是异分母分式,则必须先通分,把异分母分式化为同分母分式,然后再相加减.
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