题目内容
化简求值:[(x+2y)2﹣(x﹣2y)2﹣(x+2y)(x﹣2y)﹣4y2]÷2x,其中x=﹣2,y=
.
解:[(x+2y)2﹣(x﹣2y)2﹣(x+2y)(x﹣2y)﹣4y2]÷2x,
=[(x2+4xy+4y2)﹣(x2﹣4xy+4y2)﹣4y2]÷2x,
=(x2+4xy+4y2﹣x2+4xy﹣4y2﹣x2+4y2﹣4y2)÷2x,
=(﹣x2+8xy)÷2x,
=﹣
x+4y,
当x=﹣2,y=
时,=﹣
×(﹣2)+4×
=1+2=3.
=[(x2+4xy+4y2)﹣(x2﹣4xy+4y2)﹣4y2]÷2x,
=(x2+4xy+4y2﹣x2+4xy﹣4y2﹣x2+4y2﹣4y2)÷2x,
=(﹣x2+8xy)÷2x,
=﹣
当x=﹣2,y=
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