题目内容
分解因式:
(1)-x4+
;
(2)-8a2b+2a3+8ab2
(1)-x4+
| 1 |
| 16 |
(2)-8a2b+2a3+8ab2
(1)-x4+
,
=-(x4-
),
=-(x2+
)(x2-
),
=-(x2+
)(x+
)(x-
);
(2)-8a2b+2a3+8ab2,
=2a(a2-4ab+4b2),
=2a(a-2b)2.
| 1 |
| 16 |
=-(x4-
| 1 |
| 16 |
=-(x2+
| 1 |
| 4 |
| 1 |
| 4 |
=-(x2+
| 1 |
| 4 |
| 1 |
| 2 |
| 1 |
| 2 |
(2)-8a2b+2a3+8ab2,
=2a(a2-4ab+4b2),
=2a(a-2b)2.
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