题目内容
先化简,再求值.(| x |
| x+1 |
| x+1 |
| x2-1 |
| x2+1 |
| x2+x |
分析:解题思路:本题的关键是正确进行分式的通分、约分,并准确代值计算.
解答:解:(
+
)÷
=(
+
)÷
,(1分)
=
•
,(3分)
=
,(4分)
当x=-2009时,原式=
=
.(6分)
| x |
| x+1 |
| x+1 |
| x2-1 |
| x2+1 |
| x2+x |
=(
| x |
| x+1 |
| x+1 |
| x2-1 |
| x2+1 |
| x(x+1) |
=
| x2+1 |
| (x+1)(x-1) |
| x(x+1) |
| x2+1 |
=
| x |
| x-1 |
当x=-2009时,原式=
| -2009 |
| -2009-1 |
| 2009 |
| 2010 |
点评:本题主要考查分式的化简求值的知识点,化简是关键.
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