题目内容

解方程:
(1)x2-5=0                    (2)x2+2=3(x+2)
(3)x2+4x-1=0                 (4)(x-2)2-3(x-2)=0.
(1)x2-5=0,
x2=5,
x 1=
5
,x 2=-
5


(2)x2+2=3(x+2),
x2-3x-4=0,
(x-4)(x+1)=0,
x 1=4,x 2=-1;


(3)x2+4x-1=0,
(x+2)2=5,
x 1=-2+
5
,x 2=-2-
5


(4)(x-2)2-3(x-2)=0,
(x-2)(x-5)=0,
x 1=2,x 2=5;
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