题目内容
先化简,再求值:(| x |
| x-1 |
| 2x |
| x+1 |
| x |
| x2-1 |
分析:首先把括号里面的分式通分,再把通分的结果和
约分,最后把x=5代入化简的结果得问题答案.
| x 2-1 |
| x |
解答:解:原式=(
-
)÷
,
=
×
,
=
,
=-x+3,
∴当x=5时,原式=-5+3,
=-2.
| x(x+1) |
| (x+1)(x-1) |
| 2x(x-1) |
| (x+1)(x-1) |
| x |
| (x+1)(x-1) |
=
| -x2+3x |
| (x+1)(x-1) |
| (x+1)(x-1) |
| x |
=
| -x2+3x |
| x |
=-x+3,
∴当x=5时,原式=-5+3,
=-2.
点评:本题考查了分式的化简求值,在分式的化简中注意因式分解的运用.
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