题目内容
已知:| 1 |
| R |
| 1 |
| R1 |
| 1 |
| R2 |
分析:由已知可知
=
+
,化简可得:R1=
.
| 1 |
| R1 |
| 1 |
| R |
| 1 |
| R2 |
| RR2 |
| R+R2 |
解答:解:因为
=
-
(R1,R2,R均不为0).所以
=
+
,化简可得:R1=
.
| 1 |
| R |
| 1 |
| R1 |
| 1 |
| R2 |
| 1 |
| R1 |
| 1 |
| R |
| 1 |
| R2 |
| RR2 |
| R+R2 |
点评:本题考查了分式的加减运算.解决本题首先应通分,最后要注意将结果化为最简分式.
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已知公式
=
+
(R1≠R2),则表示R1的公式是( )
| 1 |
| R |
| 1 |
| R1 |
| 1 |
| R2 |
A、R1=
| ||
B、R1=
| ||
C、R1=
| ||
D、R1=
|