题目内容
计算:
(1)-
×[(-2)3×(-
)2-
];
(2)-24+
×[6+(-4)2].
(1)-
| 3 |
| 4 |
| 1 |
| 4 |
| 1 |
| 2 |
(2)-24+
| 1 |
| 2 |
(1)-
×[(-2)3×(-
)2-
]
=-
×[(-8)×
-
]
=-
×[-
-
]
=-
×[-1]
=
;
(2)-24+
×[6+(-4)2]
=-16+
×[6+16]
=-16+
×22
=-16+11
=-5.
| 3 |
| 4 |
| 1 |
| 4 |
| 1 |
| 2 |
=-
| 3 |
| 4 |
| 1 |
| 16 |
| 1 |
| 2 |
=-
| 3 |
| 4 |
| 1 |
| 2 |
| 1 |
| 2 |
=-
| 3 |
| 4 |
=
| 3 |
| 4 |
(2)-24+
| 1 |
| 2 |
=-16+
| 1 |
| 2 |
=-16+
| 1 |
| 2 |
=-16+11
=-5.
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