题目内容
如图,直线y=
x与双曲线y=
(x>0)交于点A,将直线y=
x向下平移个6单位后,与双曲线y=
(x>0)交于点B,与x轴交于点C,则C点的坐标为______;若
=2,则k=______.

| 4 |
| 3 |
| k |
| x |
| 4 |
| 3 |
| k |
| x |
| AO |
| BC |
∵将直线y=
x向下平移个6单位后得到直线BC,
∴直线BC解析式为:y=
x-6,
令y=0,得
x-6=0,
∴C点坐标为(
,0);
∵直线y=
x与双曲线y=
(x>0)交于点A,
∴A(
,
),
又∵直线y=
x-6与双曲线y=
(x>0)交于点B,且
=2,
∴B(
+
,
),将B的坐标代入y=
中,得
(
+
)
=k,
解得k=12.
故答案为:(
,0),12.

| 4 |
| 3 |
∴直线BC解析式为:y=
| 4 |
| 3 |
令y=0,得
| 4 |
| 3 |
∴C点坐标为(
| 9 |
| 2 |
∵直线y=
| 4 |
| 3 |
| k |
| x |
∴A(
| ||
| 2 |
2
| ||
| 3 |
又∵直线y=
| 4 |
| 3 |
| k |
| x |
| AO |
| BC |
∴B(
| 9 |
| 2 |
| ||
| 4 |
| ||
| 3 |
| k |
| x |
(
| 9 |
| 2 |
| ||
| 4 |
| ||
| 3 |
解得k=12.
故答案为:(
| 9 |
| 2 |
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