题目内容
化简求值: (1) 2a﹣3b+[4a﹣(3a﹣b)]
(2)
(﹣4x2+2x﹣8)﹣(
x﹣1),其中x=
(2)
解:(1) 2a﹣3b+[4a﹣(3a﹣b)]
=2a﹣3b+4a﹣3a+b
=3a﹣2b;
(2)
(﹣4x2+2x﹣8)﹣(
x﹣1)
=﹣x2+
x﹣2﹣
x+1
=﹣x2﹣1,
x=
时,原式=﹣
﹣1=﹣
.
=2a﹣3b+4a﹣3a+b
=3a﹣2b;
(2)
=﹣x2+
=﹣x2﹣1,
x=
练习册系列答案
相关题目