题目内容
计算:
(1)-24-
×[5-(-3)2]; (2)[-
×(-
)+(-
)÷
]÷(-2)4.
(1)-24-
| 1 |
| 2 |
| 1 |
| 3 |
| 1 |
| 2 |
| 1 |
| 9 |
| 2 |
| 3 |
(1)-24-
×[5-(-3)2]
=-16-
×[5-9]=-16-
×(-4),
=-16+2,
=-14;
(2)[-
×(-
)+(-
)÷
]÷(-2)4,
=[
-
]÷16,
=0÷16,
=0.
| 1 |
| 2 |
=-16-
| 1 |
| 2 |
| 1 |
| 2 |
=-16+2,
=-14;
(2)[-
| 1 |
| 3 |
| 1 |
| 2 |
| 1 |
| 9 |
| 2 |
| 3 |
=[
| 1 |
| 6 |
| 1 |
| 6 |
=0÷16,
=0.
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