题目内容
(1)计算:(-| 2 |
| 1 |
| 3 |
| 3 |
(2)化简:(
| 1 |
| x-2 |
| 3-x |
| x2-4 |
分析:有理数的混合运算首先要弄清楚运算顺序,先去括号,再进行有理数的乘除,最后是加减.
解答:解:(1)原式=1-3-
+2×
=-2;
(2)原式=
•
=x+2.
| 3 |
| ||
| 2 |
=-2;
(2)原式=
| 1-x+2 |
| x-2 |
| (x+2)(x-2) |
| -(x-3) |
=x+2.
点评:此题的关键是注意0指数幂和特殊角的三角函数值.
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