题目内容
先化简,再求值:
÷
+
,其中x=
+1.
| x-2 |
| x2-1 |
| 2x+2 |
| x2+2x+1 |
| 1 |
| x-1 |
| 2 |
原式=
| x-2 |
| (x+1)(x-1) |
| 2(x+1) |
| (x+1) 2 |
| 1 |
| x-1 |
=
| x-2 |
| (x+1)(x-1) |
| x+1 |
| 2 |
| 1 |
| x-1 |
=
| x-2 |
| 2(x-1) |
| 1 |
| x-1 |
=
| x |
| 2(x-1) |
当x=
| 2 |
2+
| ||
| 4 |
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题目内容
| x-2 |
| x2-1 |
| 2x+2 |
| x2+2x+1 |
| 1 |
| x-1 |
| 2 |
| x-2 |
| (x+1)(x-1) |
| 2(x+1) |
| (x+1) 2 |
| 1 |
| x-1 |
| x-2 |
| (x+1)(x-1) |
| x+1 |
| 2 |
| 1 |
| x-1 |
| x-2 |
| 2(x-1) |
| 1 |
| x-1 |
| x |
| 2(x-1) |
| 2 |
2+
| ||
| 4 |