题目内容
(2013•朝阳区二模)计算:(
-
)÷
.
| 3 |
| x-1 |
| 1 |
| x+1 |
| 2 |
| x2-1 |
分析:首先将括号里面进行通分,进而将能因式分解的分子与分母进行分解因式,再化简即可.
解答:解:(
-
)÷
=[
-
]÷
=
÷
=x+2.
| 3 |
| x-1 |
| 1 |
| x+1 |
| 2 |
| x2-1 |
=[
| 3(x+1) |
| (x+1)(x-1) |
| x+1 |
| (x+1)(x-1) |
| 2 |
| x2-1 |
=
| 2x+4 |
| (x+1)(x-1) |
| 2 |
| x2-1 |
=x+2.
点评:此题主要考查了分式的混合运算,正确根据分式的基本性质分解因式是解题关键.
练习册系列答案
相关题目