题目内容

5.方程组$\left\{\begin{array}{l}{x+y=1}\\{3x-y=-5}\end{array}\right.$的解为(  )
A.$\left\{\begin{array}{l}{x=1}\\{y=2}\end{array}\right.$B.$\left\{\begin{array}{l}{x=-1}\\{y=2}\end{array}\right.$C.$\left\{\begin{array}{l}{x=-1}\\{y=-2}\end{array}\right.$D.$\left\{\begin{array}{l}{x=1}\\{y=-2}\end{array}\right.$

分析 根据加减法,可得方程组的解.

解答 解:两式相加,得4x=-4,
解得x=-1.
把x=-1代入x+y=1,得
y=2,
方程组的解为$\left\{\begin{array}{l}{x=-1}\\{y=2}\end{array}\right.$,
故选:B.

点评 本题考查了二元一次方程组的解,利用加减法是解题关键.

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