题目内容
计算:(1)2sin30°-2cos60°+tan45°
(2)-12×
+|-3
|+2cos60°.
(2)-12×
| 27 |
| 3 |
(1)2sin30°-2cos60°+tan45°
=2×
-2×
+1
=1-1+1=1;
(2)原式=-1×3
+3
+2×
=1.
=2×
| 1 |
| 2 |
| 1 |
| 2 |
=1-1+1=1;
(2)原式=-1×3
| 3 |
| 3 |
| 1 |
| 2 |
=1.
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