题目内容
先化简,再求值:-4(-ab2+3a2b)-(3a2b-ab2),其中a=
,b=-
.
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原式=4ab2-12a2b-3a2b+ab2
=5ab2-15a2b,
当a=
,b=-
时,原式=5×
×(-
)2-15×(
)2×(-
)=
.
=5ab2-15a2b,
当a=
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