题目内容
化简| xy |
| x2-y2 |
| 1 |
| x-y |
| 1 |
| x+y |
分析:本题考查分式的混合运算,要注意运算顺序,有括号先算括号里的,再把除法转化为乘法来做,经过约分把结果化为最简.
解答:解:
÷(
-
)
=
÷(
)
=
÷
=
•
=
x.
故答案为
x.
| xy |
| x2-y2 |
| 1 |
| x-y |
| 1 |
| x+y |
=
| xy |
| x2-y2 |
| (x+y)-(x-y) |
| (x-y)(x+y) |
=
| xy |
| x2-y2 |
| 2y |
| x2-y2 |
=
| xy |
| x2-y2 |
| x2-y2 |
| 2y |
=
| 1 |
| 2 |
故答案为
| 1 |
| 2 |
点评:本题主要考查分式的混合运算,关键是通分、分解因式、约分,注意除法运算转化成乘法运算.
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