题目内容
若记y=f(x)=
,其中f(1)表示当x=1时y的值,即f(1)=
=
;f(
)表示当x=
时y的值,即f(
)=f(
)=
=
;…;则f(1)+f(2)+f(
)+f(3)+f(
)+…+f(2011)+f(
)=______.
| x2 |
| 1+x2 |
| 12 |
| 1+12 |
| 1 |
| 2 |
| 1 |
| 2 |
| 1 |
| 2 |
| 1 |
| 2 |
| 1 |
| 2 |
(
| ||
1+(
|
| 1 |
| 5 |
| 1 |
| 2 |
| 1 |
| 3 |
| 1 |
| 2011 |
∵y=f(x)=
,
∴f(
)=
=
,
∴f(x)+f(
)=1,
∴f(1)+f(2)+f(
)+f(3)+f(
)+…+f(2011)+f(
)
=f(1)+[f(2)+f(
)]+[f(3)+f(
)]+…+[f(2011)+f(
)]
=
+1+1+…+1
=
+2010
=2010
.
故答案为:2010
.
| x2 |
| 1+x2 |
∴f(
| 1 |
| x |
(
| ||
1+(
|
| 1 |
| 1+x2 |
∴f(x)+f(
| 1 |
| x |
∴f(1)+f(2)+f(
| 1 |
| 2 |
| 1 |
| 3 |
| 1 |
| 2011 |
=f(1)+[f(2)+f(
| 1 |
| 2 |
| 1 |
| 3 |
| 1 |
| 2011 |
=
| 1 |
| 2 |
=
| 1 |
| 2 |
=2010
| 1 |
| 2 |
故答案为:2010
| 1 |
| 2 |
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