题目内容
已知:如图中,∠AOB=166°,OD是∠AOC的平分线,OE是∠BOC的平分线,那么∠DOE等于______°.
∵OD是∠AOC的平分线,OE是∠BOC的平分线,
∴∠DOC=
∠AOC,∠EOC=
∠BOC,
∴∠DOE=∠DOC+∠EOC
=
∠AOC+
∠BOC
=
(∠AOC+∠BOC)
=
∠AOB
=
×166°
=83°.
故答案为:83.
∴∠DOC=
| 1 |
| 2 |
| 1 |
| 2 |
∴∠DOE=∠DOC+∠EOC
=
| 1 |
| 2 |
| 1 |
| 2 |
=
| 1 |
| 2 |
=
| 1 |
| 2 |
=
| 1 |
| 2 |
=83°.
故答案为:83.
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