题目内容
计算:
(1)3×(﹣4)+28÷(﹣7)
(2)
(3)
(4)1
+(﹣
)﹣(+
)+
.
(1)3×(﹣4)+28÷(﹣7)
(2)
(3)
(4)1
解:(1)3×(﹣4)+28÷(﹣7)
=﹣12﹣4
=﹣16;
(2)
=
×
×
=3;
(3)
=1
﹣(
×24+
×24﹣
×24)
=1
﹣(9+4﹣18)
=6
;
(4)1
+(﹣
)﹣(+
)+
=1
+
﹣
﹣
=2﹣1
=1.
=﹣12﹣4
=﹣16;
(2)
=
=3;
(3)
=1
=1
=6
(4)1
=1
=2﹣1
=1.
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