题目内容
计算:(1)(-11
| 1 |
| 7 |
| 1 |
| 5 |
| 1 |
| 7 |
| 1 |
| 5 |
| 1 |
| 3 |
| 1 |
| 3 |
(2)-8-[-7+(1-
| 2 |
| 3 |
分析:(1)逆用乘法分配律计算;
(2)按照有理数混合运算的顺序,先乘除最后算加减,有括号的先算括号里面的.
(2)按照有理数混合运算的顺序,先乘除最后算加减,有括号的先算括号里面的.
解答:解:(1)(-11
)×
+(+5
)×
+(-137
)÷5+(+113
)÷5
=(-11
)×
+(+5
)×
+(-137
)×
+(+113
)×
=
×[(-11
)+(+5
)+(-137
)+(+113
)]
=
×[-6+(-24)]
=
×(-30)
=-6.
(2)-8-[-7+(1-
×0.6)÷(-3)]
=-8-[-7+(1-
×
)×(-
)]
=-8-[-7+(1-
)×(-
)]
=-8-[-7+
×(-
)]
=-8-(-7-
)
=-8+7
=-
.
| 1 |
| 7 |
| 1 |
| 5 |
| 1 |
| 7 |
| 1 |
| 5 |
| 1 |
| 3 |
| 1 |
| 3 |
=(-11
| 1 |
| 7 |
| 1 |
| 5 |
| 1 |
| 7 |
| 1 |
| 5 |
| 1 |
| 3 |
| 1 |
| 5 |
| 1 |
| 3 |
| 1 |
| 5 |
=
| 1 |
| 5 |
| 1 |
| 7 |
| 1 |
| 7 |
| 1 |
| 3 |
| 1 |
| 3 |
=
| 1 |
| 5 |
=
| 1 |
| 5 |
=-6.
(2)-8-[-7+(1-
| 2 |
| 3 |
=-8-[-7+(1-
| 2 |
| 3 |
| 3 |
| 5 |
| 1 |
| 3 |
=-8-[-7+(1-
| 2 |
| 5 |
| 1 |
| 3 |
=-8-[-7+
| 3 |
| 5 |
| 1 |
| 3 |
=-8-(-7-
| 1 |
| 5 |
=-8+7
| 1 |
| 5 |
=-
| 4 |
| 5 |
点评:要正确掌握运算顺序,即乘方运算(和以后学习的开方运算)叫做三级运算;乘法和除法叫做二级运算;加法和减法叫做一级运算.在混合运算中要特别注意运算顺序:先三级,后二级,再一级;有括号的先算括号里面的;同级运算按从左到右的顺序.
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