题目内容
计算:
(1)(-
+
-
)÷(-
)
(2)-14-(1-0.5)×
×[2-(-3)2]
(3)|-5-4|-(-5)×(-2)2-1÷(-3)
(4)(-2x2+3x)-[5x-(2x2+1)-x2].
(1)(-
| 3 |
| 7 |
| 1 |
| 3 |
| 9 |
| 14 |
| 1 |
| 42 |
(2)-14-(1-0.5)×
| 1 |
| 3 |
(3)|-5-4|-(-5)×(-2)2-1÷(-3)
(4)(-2x2+3x)-[5x-(2x2+1)-x2].
(1)(-
+
-
)÷(-
),
=(-
+
-
)×(-42),
=18-14+27,
=31;
(2)-14-(1-0.5)×
×[2-(-3)2],
=-1-
×
×(-7),
=-1+
,
=
;
(3)|-5-4|-(-5)×(-2)2-1÷(-3),
=9-(-5)×4-(-3),
=9+20+3,
=32;
(4)(-2x2+3x)-[5x-(2x2+1)-x2],
=-2x2+3x-5x+2x2+1+x2,
=x2-2x+1.
| 3 |
| 7 |
| 1 |
| 3 |
| 9 |
| 14 |
| 1 |
| 42 |
=(-
| 3 |
| 7 |
| 1 |
| 3 |
| 9 |
| 14 |
=18-14+27,
=31;
(2)-14-(1-0.5)×
| 1 |
| 3 |
=-1-
| 1 |
| 2 |
| 1 |
| 3 |
=-1+
| 7 |
| 6 |
=
| 1 |
| 6 |
(3)|-5-4|-(-5)×(-2)2-1÷(-3),
=9-(-5)×4-(-3),
=9+20+3,
=32;
(4)(-2x2+3x)-[5x-(2x2+1)-x2],
=-2x2+3x-5x+2x2+1+x2,
=x2-2x+1.
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