题目内容

计算:
(1)(-
3
7
+
1
3
-
9
14
)÷(-
1
42
)

(2)-14-(1-0.5)×
1
3
×[2-(-3)2]

(3)|-5-4|-(-5)×(-2)2-1÷(-3)
(4)(-2x2+3x)-[5x-(2x2+1)-x2].
(1)(-
3
7
+
1
3
-
9
14
)÷(-
1
42
)

=(-
3
7
+
1
3
-
9
14
)×(-42),
=18-14+27,
=31;

(2)-14-(1-0.5)×
1
3
×[2-(-3)2]

=-1-
1
2
×
1
3
×(-7)

=-1+
7
6

=
1
6


(3)|-5-4|-(-5)×(-2)2-1÷(-3),
=9-(-5)×4-(-3),
=9+20+3,
=32;

(4)(-2x2+3x)-[5x-(2x2+1)-x2],
=-2x2+3x-5x+2x2+1+x2
=x2-2x+1.
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