题目内容
已知
=
=
,则
=
| 1 |
| x |
| 2 |
| y+z |
| 3 |
| z+x |
| 2y+z |
| x |
2
2
.分析:设
=
=
=k,推出x=k,y+z=2k,z+x=3k,求出x=k,y=0,z=2k,代入求出即可.
| x |
| 1 |
| y+z |
| 2 |
| z+x |
| 3 |
解答:解:∵
=
=
,
∴设
=
=
=k,
∴x=k,y+z=2k,z+x=3k,
∴x=k,y=0,z=2k,
∴
=
=2,
故答案为:2.
| 1 |
| x |
| 2 |
| y+z |
| 3 |
| z+x |
∴设
| x |
| 1 |
| y+z |
| 2 |
| z+x |
| 3 |
∴x=k,y+z=2k,z+x=3k,
∴x=k,y=0,z=2k,
∴
| 2y+z |
| x |
| 0+2k |
| k |
故答案为:2.
点评:本题考查了分式的约分的应用,关键是用k表示出x y z的值.
练习册系列答案
相关题目