题目内容
计算或化简:
(1)﹣22×7﹣(﹣3)×6+8;
(2)(﹣1)2009﹣(
﹣
﹣
)×24﹣(﹣2)2×3;
(3)5abc﹣2a2b﹣[3abc﹣3(4ab2+a2b)];
(4)
(﹣4x2+2x﹣8)﹣2(
x﹣1);
(5)(2x3﹣xyz)﹣2(x3﹣y3+xyz)+(xyz﹣2y3);
(6)(2x2+x)﹣2[x2﹣2(3x2﹣x)].
(1)﹣22×7﹣(﹣3)×6+8;
(2)(﹣1)2009﹣(
(3)5abc﹣2a2b﹣[3abc﹣3(4ab2+a2b)];
(4)
(5)(2x3﹣xyz)﹣2(x3﹣y3+xyz)+(xyz﹣2y3);
(6)(2x2+x)﹣2[x2﹣2(3x2﹣x)].
解:(1)原式=﹣4×7+3×6+8
=﹣28+18+8
=﹣2;
(2)原式=﹣1﹣
×24+
×24+
×24﹣4×3
=﹣1﹣18+4+9﹣12
=﹣18;
(3)原式=5abc﹣2a2b﹣[3abc﹣12ab2﹣3a2b]
=5abc﹣2a2b﹣3abc+12ab2+3a2b
=2abc+a2b+12ab2;
(4)原式=﹣x2+
x﹣2﹣x+2
=﹣x2﹣
x;
(5)原式=2x3﹣xyz﹣2x3+2y3﹣2xyz+xyz﹣2y3
=﹣2xyz;
(6)原式=2x2+x﹣2[x2﹣6x2+2x]
=2x2+x﹣2x2+12x2﹣4x
=12x2﹣3x.
=﹣28+18+8
=﹣2;
(2)原式=﹣1﹣
=﹣1﹣18+4+9﹣12
=﹣18;
(3)原式=5abc﹣2a2b﹣[3abc﹣12ab2﹣3a2b]
=5abc﹣2a2b﹣3abc+12ab2+3a2b
=2abc+a2b+12ab2;
(4)原式=﹣x2+
=﹣x2﹣
(5)原式=2x3﹣xyz﹣2x3+2y3﹣2xyz+xyz﹣2y3
=﹣2xyz;
(6)原式=2x2+x﹣2[x2﹣6x2+2x]
=2x2+x﹣2x2+12x2﹣4x
=12x2﹣3x.
练习册系列答案
相关题目