题目内容
已知
=
,则
÷(
-x-2)的值为______.
| x+3 |
| x+2 |
| 1 |
| 2sin60°+2cos45°+1 |
| x-3 |
| 2x-4 |
| 5 |
| x-2 |
∵2sin60°+2cos45°+1=2×
+2×
+1=
+
+1,
∴
=
,
解得x=-3-
+
,
∴
÷(
-x-2)=
÷
,
=
×
,
=-
,
=-
,
=
.
故答案为:
.
| ||
| 2 |
| ||
| 2 |
| 3 |
| 2 |
∴
| x+3 |
| x+2 |
| 1 | ||||
|
解得x=-3-
| 3 |
| 2 |
∴
| x-3 |
| 2x-4 |
| 5 |
| x-2 |
| x-3 |
| 2(x-2) |
| 5-(x+2)(x-2) |
| x-2 |
=
| x-3 |
| 2(x-2) |
| x-2 |
| 9-x2 |
=-
| 1 |
| 2(x+3) |
=-
| 1 | ||||
2(-3-
|
=
| ||||
| 2 |
故答案为:
| ||||
| 2 |
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